12c^2-13c-35=0

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Solution for 12c^2-13c-35=0 equation:


Simplifying
12c2 + -13c + -35 = 0

Reorder the terms:
-35 + -13c + 12c2 = 0

Solving
-35 + -13c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -4c)(7 + -3c) = 0

Subproblem 1

Set the factor '(-5 + -4c)' equal to zero and attempt to solve: Simplifying -5 + -4c = 0 Solving -5 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -4c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -4c = 0 + 5 -4c = 0 + 5 Combine like terms: 0 + 5 = 5 -4c = 5 Divide each side by '-4'. c = -1.25 Simplifying c = -1.25

Subproblem 2

Set the factor '(7 + -3c)' equal to zero and attempt to solve: Simplifying 7 + -3c = 0 Solving 7 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -3c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -3c = 0 + -7 -3c = 0 + -7 Combine like terms: 0 + -7 = -7 -3c = -7 Divide each side by '-3'. c = 2.333333333 Simplifying c = 2.333333333

Solution

c = {-1.25, 2.333333333}

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